diff options
Diffstat (limited to 'lib/pelt.py')
-rw-r--r-- | lib/pelt.py | 261 |
1 files changed, 261 insertions, 0 deletions
diff --git a/lib/pelt.py b/lib/pelt.py new file mode 100644 index 0000000..ddc2324 --- /dev/null +++ b/lib/pelt.py @@ -0,0 +1,261 @@ +#!/usr/bin/env python3 + +import numpy as np +import ruptures +from multiprocessing import Pool + +# returns the found changepoints by algo for the specific penalty pen. +# algo should be the return value of Pelt(...).fit(signal) +# Also puts a token in container q to let the progressmeter know the changepoints for penalty pen +# have been calculated. +# used for parallel calculation of changepoints vs penalty +def _get_breakpoints(algo, pen): + return pen, len(algo.predict(pen=pen)) + + +def find_knee_point(data_x, data_y, S=1.0, curve="convex", direction="decreasing"): + kneedle = kneed.KneeLocator(data_x, data_y, S=S, curve=curve, direction=direction) + kneepoint = (kneedle.knee, kneedle.knee_y) + return kneepoint + + +def norm_signal(signal, scaler=25): + max_val = max(signal) + normed_signal = np.zeros(shape=len(signal)) + for i, signal_i in enumerate(signal): + normed_signal[i] = signal_i / max_val + normed_signal[i] = normed_signal[i] * scaler + return normed_signal + + +class PELT: + def __init__(self, **kwargs): + # Defaults von Janis + self.jump = 1 + self.refinement_threshold = 100 + self.range_min = 0 + self.range_max = 100 + self.__dict__.update(kwargs) + + # signals: a set of uW measurements belonging to a single parameter configuration (i.e., a single by_param entry) + def needs_refinement(self, signals): + count = 0 + for signal in signals: + p1, median, p99 = np.percentile(signal, (1, 50, 99)) + + if median - p1 > self.refinement_threshold: + count += 1 + elif p99 - median > self.refinement_threshold: + count += 1 + refinement_ratio = count / len(signals) + return refinement_ratio > 0.3 + + def get_penalty_value( + self, signals, model="l1", min_dist=2, range_min=0, range_max=100, S=1.0 + ): + # Janis macht hier noch kein norm_signal. Mit sieht es aber genau so brauchbar aus. + signal = norm_signal(signals[0]) + algo = ruptures.Pelt(model=model, jump=self.jump, min_size=min_dist).fit(signal) + queue = list() + for i in range(range_min, range_max + 1): + queue.append((algo, i)) + with Pool() as pool: + results = pool.starmap(_get_breakpoints, queue) + pen_val = [x[0] for x in results] + changepoint_counts = [x[1] for x in results] + # Scheint unnötig zu sein, da wir ohnehin plateau detection durchführen + # knee = find_knee_point(pen_val, changepoint_counts, S=S) + knee = (0,) + + start_index = -1 + end_index = -1 + longest_start = -1 + longest_end = -1 + prev_val = -1 + for i, num_bkpts in enumerate(changepoint_counts[knee[0] :]): + if num_bkpts != prev_val: + end_index = i - 1 + if end_index - start_index > longest_end - longest_start: + # currently found sequence is the longest found yet + longest_start = start_index + longest_end = end_index + start_index = i + if i == len(changepoint_counts[knee[0] :]) - 1: + # end sequence with last value + end_index = i + # # since it is not guaranteed that this is the end of the plateau, assume the mid + # # of the plateau was hit. + # size = end_index - start_index + # end_index = end_index + size + # However this is not the clean solution. Better if search interval is widened + # with range_min and range_max + if end_index - start_index > longest_end - longest_start: + # last found sequence is the longest found yet + longest_start = start_index + longest_end = end_index + start_index = i + prev_val = num_bkpts + mid_of_plat = longest_start + (longest_end - longest_start) // 2 + knee = (mid_of_plat + knee[0], changepoint_counts[mid_of_plat + knee[0]]) + + # modify knee according to options. Defaults to 1 * knee + knee = (knee[0] * 1, knee[1]) + return knee + + """ + # calculates and returns the necessary penalty for signal. Parallel execution with num_processes many processes + # jump, min_dist are passed directly to PELT. S is directly passed to kneedle. + # pen_modifier is used as a factor on the resulting penalty. + # the interval [range_min, range_max] is used for searching. + def calculate_penalty_value( + signal, + model="l1", + jump=5, + min_dist=2, + range_min=0, + range_max=100, + S=1.0, + pen_modifier=None, + show_plots=False, + ): + # default params in Function + if model is None: + model = "l1" + if jump is None: + jump = 5 + if min_dist is None: + min_dist = 2 + if range_min is None: + range_min = 0 + if range_max is None: + range_max = 50 + if S is None: + S = 1.0 + if pen_modifier is None: + pen_modifier = 1 + # change point detection. best fit seemingly with l1. rbf prods. RuntimeErr for pen > 30 + # https://ctruong.perso.math.cnrs.fr/ruptures-docs/build/html/costs/index.html + # model = "l1" #"l1" # "l2", "rbf" + algo = ruptures.Pelt(model=model, jump=jump, min_size=min_dist).fit(signal) + + ### CALC BKPS WITH DIFF PENALTYS + if range_max != range_min: + # building args array for parallelizing + args = [] + # for displaying progression + m = Manager() + q = m.Queue() + + for i in range(range_min, range_max + 1): + # same calculation for all except other penalty + args.append((algo, i, q)) + + print_info("starting kneepoint calculation.") + # init Pool with num_proesses + with Pool() as p: + # collect results from pool + result = p.starmap_async(get_bkps, args) + # monitor loop + percentage = -100 # Force display of 0% + i = 0 + while True: + if result.ready(): + break + + size = q.qsize() + last_percentage = percentage + percentage = round(size / (range_max - range_min) * 100, 2) + if percentage >= last_percentage + 2 or i >= refresh_thresh: + print_info("Current progress: " + str(percentage) + "%") + i = 0 + else: + i += 1 + time.sleep(refresh_delay) + res = result.get() + print_info("Finished kneepoint calculation.") + # DECIDE WHICH PENALTY VALUE TO CHOOSE ACCORDING TO ELBOW/KNEE APPROACH + # split x and y coords to pass to kneedle + pen_val = [x[0] for x in res] + fitted_bkps_val = [x[1] for x in res] + # # plot to look at res + knee = find_knee_point(pen_val, fitted_bkps_val, S=S) + + # TODO: Find plateau on pen_val vs fitted_bkps_val + # scipy.find_peaks() does not find plateaus if they extend through the end of the data. + # to counter that, add one extremely large value to the right side of the data + # after negating it is extremely small -> Almost certainly smaller than the + # found plateau therefore the plateau does not extend through the border + # -> scipy.find_peaks finds it. Choose value from within that plateau. + # fitted_bkps_val.append(100000000) + # TODO: Approaching over find_peaks might not work if the initial decrease step to the + # "correct" number of changepoints and additional decrease steps e.g. underfitting + # take place within the given penalty interval. find_peak only finds plateaus + # of peaks. If the number of chpts decreases after the wanted plateau the condition + # for local peaks is not satisfied anymore. Therefore this approach will only work + # if the plateau extends over the right border of the penalty interval. + # peaks, peak_plateaus = find_peaks(- np.array(fitted_bkps_val), plateau_size=1) + # Since the data is monotonously decreasing only one plateau can be found. + + # assuming the plateau is constant, i.e. no noise. OK to assume this here, since num_bkpts + # is monotonously decreasing. If the number of bkpts decreases inside a considered + # plateau, it means that the stable configuration is not yet met. -> Search further + start_index = -1 + end_index = -1 + longest_start = -1 + longest_end = -1 + prev_val = -1 + for i, num_bkpts in enumerate(fitted_bkps_val[knee[0] :]): + if num_bkpts != prev_val: + end_index = i - 1 + if end_index - start_index > longest_end - longest_start: + # currently found sequence is the longest found yet + longest_start = start_index + longest_end = end_index + start_index = i + if i == len(fitted_bkps_val[knee[0] :]) - 1: + # end sequence with last value + end_index = i + # # since it is not guaranteed that this is the end of the plateau, assume the mid + # # of the plateau was hit. + # size = end_index - start_index + # end_index = end_index + size + # However this is not the clean solution. Better if search interval is widened + # with range_min and range_max + if end_index - start_index > longest_end - longest_start: + # last found sequence is the longest found yet + longest_start = start_index + longest_end = end_index + start_index = i + prev_val = num_bkpts + if show_plots: + plt.xlabel("Penalty") + plt.ylabel("Number of Changepoints") + plt.plot(pen_val, fitted_bkps_val) + plt.vlines( + longest_start + knee[0], 0, max(fitted_bkps_val), linestyles="dashed" + ) + plt.vlines( + longest_end + knee[0], 0, max(fitted_bkps_val), linestyles="dashed" + ) + plt.show() + # choosing pen from plateau + mid_of_plat = longest_start + (longest_end - longest_start) // 2 + knee = (mid_of_plat + knee[0], fitted_bkps_val[mid_of_plat + knee[0]]) + + # modify knee according to options. Defaults to 1 * knee + knee = (knee[0] * pen_modifier, knee[1]) + + else: + # range_min == range_max. has the same effect as pen_override + knee = (range_min, None) + print_info(str(knee[0]) + " has been selected as penalty.") + if knee[0] is not None: + return knee + + print_error( + "With the current thresh-hold S=" + + str(S) + + " it is not possible to select a penalty value." + ) + sys.exit(-1) + """ |